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12273415433 = 80891517297
BaseRepresentation
bin10110110111000110…
…10111010100001001
31011200100121002210222
423123203113110021
5200113443243213
65345513515425
7613101211166
oct133343272411
934610532728
1012273415433
115229028744
122466412b75
1312079b50c6
1484607106d
154bc77c808
hex2db8d7509

12273415433 has 4 divisors (see below), whose sum is σ = 12274940820. Its totient is φ = 12271890048.

The previous prime is 12273415423. The next prime is 12273415463. The reversal of 12273415433 is 33451437221.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 6373946569 + 5899468864 = 79837^2 + 76808^2 .

It is a cyclic number.

It is not a de Polignac number, because 12273415433 - 224 = 12256638217 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12273415393 and 12273415402.

It is not an unprimeable number, because it can be changed into a prime (12273415403) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 750560 + ... + 766737.

It is an arithmetic number, because the mean of its divisors is an integer number (3068735205).

Almost surely, 212273415433 is an apocalyptic number.

It is an amenable number.

12273415433 is a deficient number, since it is larger than the sum of its proper divisors (1525387).

12273415433 is an equidigital number, since it uses as much as digits as its factorization.

12273415433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1525386.

The product of its digits is 60480, while the sum is 35.

The spelling of 12273415433 in words is "twelve billion, two hundred seventy-three million, four hundred fifteen thousand, four hundred thirty-three".

Divisors: 1 8089 1517297 12273415433