Base | Representation |
---|---|
bin | 10001111000000010011… |
… | …000101010101011001011 |
3 | 11100102201100120111101120 |
4 | 101320002120222223023 |
5 | 130111231032323324 |
6 | 2340153001250323 |
7 | 154514625251316 |
oct | 21700230525313 |
9 | 4312640514346 |
10 | 1228400667339 |
11 | 433a6417489a |
12 | 17a0a4a939a3 |
13 | 8bab751ba01 |
14 | 436523b397d |
15 | 21e481e8179 |
hex | 11e0262aacb |
1228400667339 has 8 divisors (see below), whose sum is σ = 1638371063952. Its totient is φ = 818682024480.
The previous prime is 1228400667331. The next prime is 1228400667353. The reversal of 1228400667339 is 9337660048221.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 1228400667339 - 23 = 1228400667331 is a prime.
It is a Smith number, since the sum of its digits (51) coincides with the sum of the digits of its prime factors. Since it is squarefree, it is also a hoax number.
It is a junction number, because it is equal to n+sod(n) for n = 1228400667291 and 1228400667300.
It is not an unprimeable number, because it can be changed into a prime (1228400667331) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 62927052 + ... + 62946569.
It is an arithmetic number, because the mean of its divisors is an integer number (204796382994).
Almost surely, 21228400667339 is an apocalyptic number.
1228400667339 is a deficient number, since it is larger than the sum of its proper divisors (409970396613).
1228400667339 is a wasteful number, since it uses less digits than its factorization.
1228400667339 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 125876877.
The product of its (nonzero) digits is 2612736, while the sum is 51.
The spelling of 1228400667339 in words is "one trillion, two hundred twenty-eight billion, four hundred million, six hundred sixty-seven thousand, three hundred thirty-nine".
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