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12293787901433 is a prime number
BaseRepresentation
bin1011001011100101111011…
…0111000101110111111001
31121112021102012211211022212
42302321132313011313321
53102410134200321213
642051404352224505
72406124344662333
oct262713667056771
947467365754285
1012293787901433
113a0a847854545
12146675083b135
136b23b752060c
14307045aa0453
15164bca04c9a8
hexb2e5edc5df9

12293787901433 has 2 divisors, whose sum is σ = 12293787901434. Its totient is φ = 12293787901432.

The previous prime is 12293787901427. The next prime is 12293787901517. The reversal of 12293787901433 is 33410978739221.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 8295995596729 + 3997792304704 = 2880277^2 + 1999448^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12293787901433 is a prime.

It is a super-2 number, since 2×122937879014332 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (12293787901033) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6146893950716 + 6146893950717.

It is an arithmetic number, because the mean of its divisors is an integer number (6146893950717).

Almost surely, 212293787901433 is an apocalyptic number.

It is an amenable number.

12293787901433 is a deficient number, since it is larger than the sum of its proper divisors (1).

12293787901433 is an equidigital number, since it uses as much as digits as its factorization.

12293787901433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 13716864, while the sum is 59.

The spelling of 12293787901433 in words is "twelve trillion, two hundred ninety-three billion, seven hundred eighty-seven million, nine hundred one thousand, four hundred thirty-three".