Base | Representation |
---|---|
bin | 11011111101111001110011… |
… | …011111010010000011111011 |
3 | 121010111210121212202122101101 |
4 | 123331321303133102003323 |
5 | 112110222440004100011 |
6 | 1113333550512232231 |
7 | 34623354446614516 |
oct | 3375716337220373 |
9 | 533453555678341 |
10 | 123001211003131 |
11 | 3621257aa8151a |
12 | 1196656083b677 |
13 | 5382c6cb04376 |
14 | 225340cb1bd7d |
15 | e3482535a2c1 |
hex | 6fde737d20fb |
123001211003131 has 4 divisors (see below), whose sum is σ = 126968992003264. Its totient is φ = 119033430003000.
The previous prime is 123001211003123. The next prime is 123001211003173. The reversal of 123001211003131 is 131300112100321.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 123001211003131 - 23 = 123001211003123 is a prime.
It is a super-2 number, since 2×1230012110031312 (a number of 29 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 123001211003099 and 123001211003108.
It is not an unprimeable number, because it can be changed into a prime (123001211003191) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (31) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1983890500020 + ... + 1983890500081.
It is an arithmetic number, because the mean of its divisors is an integer number (31742248000816).
Almost surely, 2123001211003131 is an apocalyptic number.
123001211003131 is a deficient number, since it is larger than the sum of its proper divisors (3967781000133).
123001211003131 is an equidigital number, since it uses as much as digits as its factorization.
123001211003131 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3967781000132.
The product of its (nonzero) digits is 108, while the sum is 19.
Adding to 123001211003131 its reverse (131300112100321), we get a palindrome (254301323103452).
The spelling of 123001211003131 in words is "one hundred twenty-three trillion, one billion, two hundred eleven million, three thousand, one hundred thirty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.072 sec. • engine limits •