Base | Representation |
---|---|
bin | 1011001011111101100100… |
… | …1000000101100000011111 |
3 | 1121112212210111102100120000 |
4 | 2302333121020011200133 |
5 | 3103011133320102111 |
6 | 42054334214225343 |
7 | 2406440535105336 |
oct | 262773110054037 |
9 | 47485714370500 |
10 | 12300134144031 |
11 | 3a12504073538 |
12 | 1467a22055253 |
13 | 6b2b89258256 |
14 | 30748887cd1d |
15 | 164e4c27ac56 |
hex | b2fd920581f |
12300134144031 has 20 divisors (see below), whose sum is σ = 18518953804032. Its totient is φ = 8135521789248.
The previous prime is 12300134144029. The next prime is 12300134144057. The reversal of 12300134144031 is 13044143100321.
12300134144031 is a `hidden beast` number, since 1 + 230 + 0 + 13 + 4 + 14 + 403 + 1 = 666.
12300134144031 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 12300134144031 - 21 = 12300134144029 is a prime.
It is a super-2 number, since 2×123001341440312 (a number of 27 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (27).
It is a junction number, because it is equal to n+sod(n) for n = 12300134143986 and 12300134144004.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12300134144021) by changing a digit.
It is a polite number, since it can be written in 19 ways as a sum of consecutive naturals, for example, 597838170 + ... + 597858743.
Almost surely, 212300134144031 is an apocalyptic number.
12300134144031 is a deficient number, since it is larger than the sum of its proper divisors (6218819660001).
12300134144031 is a wasteful number, since it uses less digits than its factorization.
12300134144031 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1195697052 (or 1195697043 counting only the distinct ones).
The product of its (nonzero) digits is 3456, while the sum is 27.
Adding to 12300134144031 its reverse (13044143100321), we get a palindrome (25344277244352).
The spelling of 12300134144031 in words is "twelve trillion, three hundred billion, one hundred thirty-four million, one hundred forty-four thousand, thirty-one".
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