Search a number
-
+
12300135410491 is a prime number
BaseRepresentation
bin1011001011111101100100…
…1100111010101100111011
31121112212210120210200210221
42302333121030322230323
53103011134131113431
642054334301320511
72406440551631545
oct262773114725473
947485716720727
1012300135410491
113a12504858aa5
121467a22566137
136b2b895ac836
14307488acc695
15164e4c42b111
hexb2fd933ab3b

12300135410491 has 2 divisors, whose sum is σ = 12300135410492. Its totient is φ = 12300135410490.

The previous prime is 12300135410477. The next prime is 12300135410579. The reversal of 12300135410491 is 19401453100321.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 12300135410491 - 215 = 12300135377723 is a prime.

It is a super-2 number, since 2×123001354104912 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (12300135410441) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6150067705245 + 6150067705246.

It is an arithmetic number, because the mean of its divisors is an integer number (6150067705246).

Almost surely, 212300135410491 is an apocalyptic number.

12300135410491 is a deficient number, since it is larger than the sum of its proper divisors (1).

12300135410491 is an equidigital number, since it uses as much as digits as its factorization.

12300135410491 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12960, while the sum is 34.

The spelling of 12300135410491 in words is "twelve trillion, three hundred billion, one hundred thirty-five million, four hundred ten thousand, four hundred ninety-one".