Base | Representation |
---|---|
bin | 1011001011111101100100… |
… | …1100111010101100111011 |
3 | 1121112212210120210200210221 |
4 | 2302333121030322230323 |
5 | 3103011134131113431 |
6 | 42054334301320511 |
7 | 2406440551631545 |
oct | 262773114725473 |
9 | 47485716720727 |
10 | 12300135410491 |
11 | 3a12504858aa5 |
12 | 1467a22566137 |
13 | 6b2b895ac836 |
14 | 307488acc695 |
15 | 164e4c42b111 |
hex | b2fd933ab3b |
12300135410491 has 2 divisors, whose sum is σ = 12300135410492. Its totient is φ = 12300135410490.
The previous prime is 12300135410477. The next prime is 12300135410579. The reversal of 12300135410491 is 19401453100321.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12300135410491 - 215 = 12300135377723 is a prime.
It is a super-2 number, since 2×123001354104912 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (12300135410441) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6150067705245 + 6150067705246.
It is an arithmetic number, because the mean of its divisors is an integer number (6150067705246).
Almost surely, 212300135410491 is an apocalyptic number.
12300135410491 is a deficient number, since it is larger than the sum of its proper divisors (1).
12300135410491 is an equidigital number, since it uses as much as digits as its factorization.
12300135410491 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 12960, while the sum is 34.
The spelling of 12300135410491 in words is "twelve trillion, three hundred billion, one hundred thirty-five million, four hundred ten thousand, four hundred ninety-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.070 sec. • engine limits •