Base | Representation |
---|---|
bin | 1011001100000000111101… |
… | …1001000001010111110001 |
3 | 1121112222010221111221011011 |
4 | 2303000033121001113301 |
5 | 3103020014401200301 |
6 | 42055004415350521 |
7 | 2406502231336435 |
oct | 263001731012761 |
9 | 47488127457134 |
10 | 12301044553201 |
11 | 3a12930a65408 |
12 | 1468036b22441 |
13 | 6b2ca2a577c1 |
14 | 3075337489c5 |
15 | 164ea2161a51 |
hex | b300f6415f1 |
12301044553201 has 2 divisors, whose sum is σ = 12301044553202. Its totient is φ = 12301044553200.
The previous prime is 12301044553159. The next prime is 12301044553211. The reversal of 12301044553201 is 10235544010321.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11780408707600 + 520635845601 = 3432260^2 + 721551^2 .
It is a cyclic number.
It is not a de Polignac number, because 12301044553201 - 27 = 12301044553073 is a prime.
It is not a weakly prime, because it can be changed into another prime (12301044553211) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6150522276600 + 6150522276601.
It is an arithmetic number, because the mean of its divisors is an integer number (6150522276601).
Almost surely, 212301044553201 is an apocalyptic number.
It is an amenable number.
12301044553201 is a deficient number, since it is larger than the sum of its proper divisors (1).
12301044553201 is an equidigital number, since it uses as much as digits as its factorization.
12301044553201 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 14400, while the sum is 31.
Adding to 12301044553201 its reverse (10235544010321), we get a palindrome (22536588563522).
The spelling of 12301044553201 in words is "twelve trillion, three hundred one billion, forty-four million, five hundred fifty-three thousand, two hundred one".
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