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123013300130122 = 261506650065061
BaseRepresentation
bin11011111110000101000100…
…000011101001000101001010
3121010112221211101120220222111
4123332011010003221011022
5112110422214313130442
61113343310244212534
734624263152526643
oct3376050403510512
9533487741526874
10123013300130122
1136217713a78566
121196897539a14a
13538414857364c
142253c384da6ca
15e34cd1833b17
hex6fe1440e914a

123013300130122 has 4 divisors (see below), whose sum is σ = 184519950195186. Its totient is φ = 61506650065060.

The previous prime is 123013300130113. The next prime is 123013300130153. The reversal of 123013300130122 is 221031003310321.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 64544047312761 + 58469252817361 = 8033931^2 + 7646519^2 .

It is a junction number, because it is equal to n+sod(n) for n = 123013300130093 and 123013300130102.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 30753325032529 + ... + 30753325032532.

Almost surely, 2123013300130122 is an apocalyptic number.

123013300130122 is a deficient number, since it is larger than the sum of its proper divisors (61506650065064).

123013300130122 is an equidigital number, since it uses as much as digits as its factorization.

123013300130122 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 61506650065063.

The product of its (nonzero) digits is 648, while the sum is 22.

Adding to 123013300130122 its reverse (221031003310321), we get a palindrome (344044303440443).

The spelling of 123013300130122 in words is "one hundred twenty-three trillion, thirteen billion, three hundred million, one hundred thirty thousand, one hundred twenty-two".

Divisors: 1 2 61506650065061 123013300130122