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123015313104331 is a prime number
BaseRepresentation
bin11011111110000110111100…
…000010100001110111001011
3121010120011000200100121110211
4123332012330002201313023
5112110440330123314311
61113344242113221551
734624364064526264
oct3376067402416713
9533504020317424
10123015313104331
113621855727690a
12119692375618b7
1353843a961124b
142253d899b196b
15e34d9d40a821
hex6fe1bc0a1dcb

123015313104331 has 2 divisors, whose sum is σ = 123015313104332. Its totient is φ = 123015313104330.

The previous prime is 123015313104319. The next prime is 123015313104349. The reversal of 123015313104331 is 133401313510321.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-123015313104331 is a prime.

It is a super-2 number, since 2×1230153131043312 (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 123015313104293 and 123015313104302.

It is not a weakly prime, because it can be changed into another prime (123015313104371) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61507656552165 + 61507656552166.

It is an arithmetic number, because the mean of its divisors is an integer number (61507656552166).

Almost surely, 2123015313104331 is an apocalyptic number.

123015313104331 is a deficient number, since it is larger than the sum of its proper divisors (1).

123015313104331 is an equidigital number, since it uses as much as digits as its factorization.

123015313104331 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 9720, while the sum is 31.

Adding to 123015313104331 its reverse (133401313510321), we get a palindrome (256416626614652).

The spelling of 123015313104331 in words is "one hundred twenty-three trillion, fifteen billion, three hundred thirteen million, one hundred four thousand, three hundred thirty-one".