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123021412433 is a prime number
BaseRepresentation
bin111001010010010100…
…1011100100001010001
3102202112120111021011122
41302210221130201101
54003421440144213
6132303143452025
711613404516003
oct1624451344121
9382476437148
10123021412433
114819a41aa97
121ba13757015
13b7a7157b8a
145d50724373
153300378d08
hex1ca4a5c851

123021412433 has 2 divisors, whose sum is σ = 123021412434. Its totient is φ = 123021412432.

The previous prime is 123021412331. The next prime is 123021412457. The reversal of 123021412433 is 334214120321.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 123020652049 + 760384 = 350743^2 + 872^2 .

It is a cyclic number.

It is not a de Polignac number, because 123021412433 - 28 = 123021412177 is a prime.

It is not a weakly prime, because it can be changed into another prime (123021412463) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61510706216 + 61510706217.

It is an arithmetic number, because the mean of its divisors is an integer number (61510706217).

Almost surely, 2123021412433 is an apocalyptic number.

It is an amenable number.

123021412433 is a deficient number, since it is larger than the sum of its proper divisors (1).

123021412433 is an equidigital number, since it uses as much as digits as its factorization.

123021412433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3456, while the sum is 26.

Adding to 123021412433 its reverse (334214120321), we get a palindrome (457235532754).

The spelling of 123021412433 in words is "one hundred twenty-three billion, twenty-one million, four hundred twelve thousand, four hundred thirty-three".