Base | Representation |
---|---|
bin | 11011111110001110001100… |
… | …001111110011100101001011 |
3 | 121010120220010110001112010011 |
4 | 123332032030033303211023 |
5 | 112111102302402304003 |
6 | 1113352011003332351 |
7 | 34625061063414415 |
oct | 3376161417634513 |
9 | 533526113045104 |
10 | 123023101213003 |
11 | 3622089347a162 |
12 | 1196a84b8210b7 |
13 | 538504ac95684 |
14 | 22544c807d9b5 |
15 | e351a6eed46d |
hex | 6fe38c3f394b |
123023101213003 has 2 divisors, whose sum is σ = 123023101213004. Its totient is φ = 123023101213002.
The previous prime is 123023101212997. The next prime is 123023101213031. The reversal of 123023101213003 is 300312101320321.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 123023101213003 - 25 = 123023101212971 is a prime.
It is not a weakly prime, because it can be changed into another prime (123023101213603) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61511550606501 + 61511550606502.
It is an arithmetic number, because the mean of its divisors is an integer number (61511550606502).
Almost surely, 2123023101213003 is an apocalyptic number.
123023101213003 is a deficient number, since it is larger than the sum of its proper divisors (1).
123023101213003 is an equidigital number, since it uses as much as digits as its factorization.
123023101213003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 648, while the sum is 22.
Adding to 123023101213003 its reverse (300312101320321), we get a palindrome (423335202533324).
The spelling of 123023101213003 in words is "one hundred twenty-three trillion, twenty-three billion, one hundred one million, two hundred thirteen thousand, three".
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