Search a number
-
+
123030133113 = 341010044371
BaseRepresentation
bin111001010010100101…
…0101101100101111001
3102202120011220022200210
41302211022231211321
54003431203224423
6132304054421333
711613541606506
oct1624512554571
9382504808623
10123030133113
11481a4336a68
121ba16661849
13b7a8bbc344
145d519544ad
153300eecb93
hex1ca52ad979

123030133113 has 4 divisors (see below), whose sum is σ = 164040177488. Its totient is φ = 82020088740.

The previous prime is 123030133091. The next prime is 123030133117. The reversal of 123030133113 is 311331030321.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 123030133113 - 216 = 123030067577 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 123030133113.

It is not an unprimeable number, because it can be changed into a prime (123030133117) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20505022183 + ... + 20505022188.

It is an arithmetic number, because the mean of its divisors is an integer number (41010044372).

Almost surely, 2123030133113 is an apocalyptic number.

It is an amenable number.

123030133113 is a deficient number, since it is larger than the sum of its proper divisors (41010044375).

123030133113 is an equidigital number, since it uses as much as digits as its factorization.

123030133113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 41010044374.

The product of its (nonzero) digits is 486, while the sum is 21.

Adding to 123030133113 its reverse (311331030321), we get a palindrome (434361163434).

The spelling of 123030133113 in words is "one hundred twenty-three billion, thirty million, one hundred thirty-three thousand, one hundred thirteen".

Divisors: 1 3 41010044371 123030133113