Base | Representation |
---|---|
bin | 11011111110010100101111… |
… | …110010110010000010101001 |
3 | 121010121120021222211202000002 |
4 | 123332110233302302002221 |
5 | 112111211211322111431 |
6 | 1113355133245552345 |
7 | 34625430363415145 |
oct | 3376245762620251 |
9 | 533546258752002 |
10 | 123030140035241 |
11 | 3622387572a51a |
12 | 11970094b756b5 |
13 | 538590034204a |
14 | 2254994c24225 |
15 | e35469e353cb |
hex | 6fe52fcb20a9 |
123030140035241 has 2 divisors, whose sum is σ = 123030140035242. Its totient is φ = 123030140035240.
The previous prime is 123030140035157. The next prime is 123030140035273. The reversal of 123030140035241 is 142530041030321.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 95962791523600 + 27067348511641 = 9796060^2 + 5202629^2 .
It is a cyclic number.
It is not a de Polignac number, because 123030140035241 - 226 = 123030072926377 is a prime.
It is not a weakly prime, because it can be changed into another prime (123030140035291) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61515070017620 + 61515070017621.
It is an arithmetic number, because the mean of its divisors is an integer number (61515070017621).
Almost surely, 2123030140035241 is an apocalyptic number.
It is an amenable number.
123030140035241 is a deficient number, since it is larger than the sum of its proper divisors (1).
123030140035241 is an equidigital number, since it uses as much as digits as its factorization.
123030140035241 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8640, while the sum is 29.
Adding to 123030140035241 its reverse (142530041030321), we get a palindrome (265560181065562).
The spelling of 123030140035241 in words is "one hundred twenty-three trillion, thirty billion, one hundred forty million, thirty-five thousand, two hundred forty-one".
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