Base | Representation |
---|---|
bin | 11011111110010101110001… |
… | …101011011100111111011011 |
3 | 121010121200011000210121110212 |
4 | 123332111301223130333123 |
5 | 112111220442311112032 |
6 | 1113355435054001335 |
7 | 34625466645065645 |
oct | 3376256153347733 |
9 | 533550130717425 |
10 | 123031245410267 |
11 | 362242926860a7 |
12 | 119703431a624b |
13 | 5385a483553cc |
14 | 2254a5b961895 |
15 | e354d1ecdbb2 |
hex | 6fe571adcfdb |
123031245410267 has 2 divisors, whose sum is σ = 123031245410268. Its totient is φ = 123031245410266.
The previous prime is 123031245410197. The next prime is 123031245410279. The reversal of 123031245410267 is 762014542130321.
It is a strong prime.
It is an emirp because it is prime and its reverse (762014542130321) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 123031245410267 - 214 = 123031245393883 is a prime.
It is a super-2 number, since 2×1230312454102672 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (123031245410287) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61515622705133 + 61515622705134.
It is an arithmetic number, because the mean of its divisors is an integer number (61515622705134).
Almost surely, 2123031245410267 is an apocalyptic number.
123031245410267 is a deficient number, since it is larger than the sum of its proper divisors (1).
123031245410267 is an equidigital number, since it uses as much as digits as its factorization.
123031245410267 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 241920, while the sum is 41.
Adding to 123031245410267 its reverse (762014542130321), we get a palindrome (885045787540588).
The spelling of 123031245410267 in words is "one hundred twenty-three trillion, thirty-one billion, two hundred forty-five million, four hundred ten thousand, two hundred sixty-seven".
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