Base | Representation |
---|---|
bin | 1011001100001000101111… |
… | …0111110100011001101011 |
3 | 1121120011112111022002101121 |
4 | 2303002023313310121223 |
5 | 3103033304022020243 |
6 | 42055551542200111 |
7 | 2406605051011453 |
oct | 263021367643153 |
9 | 47504474262347 |
10 | 12303133001323 |
11 | 3a1380292339a |
12 | 146851a423037 |
13 | 6b324662c618 |
14 | 307690c68d63 |
15 | 1650756961ed |
hex | b308bdf466b |
12303133001323 has 2 divisors, whose sum is σ = 12303133001324. Its totient is φ = 12303133001322.
The previous prime is 12303133001311. The next prime is 12303133001353. The reversal of 12303133001323 is 32310033130321.
It is a weak prime.
It is an emirp because it is prime and its reverse (32310033130321) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 12303133001323 - 29 = 12303133000811 is a prime.
It is a super-3 number, since 3×123031330013233 (a number of 40 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (12303133001353) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6151566500661 + 6151566500662.
It is an arithmetic number, because the mean of its divisors is an integer number (6151566500662).
Almost surely, 212303133001323 is an apocalyptic number.
12303133001323 is a deficient number, since it is larger than the sum of its proper divisors (1).
12303133001323 is an equidigital number, since it uses as much as digits as its factorization.
12303133001323 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2916, while the sum is 25.
Adding to 12303133001323 its reverse (32310033130321), we get a palindrome (44613166131644).
The spelling of 12303133001323 in words is "twelve trillion, three hundred three billion, one hundred thirty-three million, one thousand, three hundred twenty-three".
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