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123031401242011 = 136190397796651
BaseRepresentation
bin11011111110010101111010…
…111101111001110110011011
3121010121200112220000200102221
4123332111322331321312123
5112111221302204221021
61113355502342004511
734625503546454623
oct3376257275716633
9533550486020387
10123031401242011
1136224362640869
1211970387416737
135385a71716842
142254a74527883
15e354e0a11241
hex6fe57af79d9b

123031401242011 has 4 divisors (see below), whose sum is σ = 123121799040024. Its totient is φ = 122941003444000.

The previous prime is 123031401241921. The next prime is 123031401242021. The reversal of 123031401242011 is 110242104130321.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 123031401242011 - 215 = 123031401209243 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (123031401242021) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 45198896965 + ... + 45198899686.

It is an arithmetic number, because the mean of its divisors is an integer number (30780449760006).

Almost surely, 2123031401242011 is an apocalyptic number.

123031401242011 is a deficient number, since it is larger than the sum of its proper divisors (90397798013).

123031401242011 is an equidigital number, since it uses as much as digits as its factorization.

123031401242011 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 90397798012.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 123031401242011 its reverse (110242104130321), we get a palindrome (233273505372332).

The spelling of 123031401242011 in words is "one hundred twenty-three trillion, thirty-one billion, four hundred one million, two hundred forty-two thousand, eleven".

Divisors: 1 1361 90397796651 123031401242011