Base | Representation |
---|---|
bin | 1011001100001001000111… |
… | …0101101101100100011011 |
3 | 1121120011210110200020220022 |
4 | 2303002101311231210123 |
5 | 3103034010134043342 |
6 | 42100005520021055 |
7 | 2406610404645362 |
oct | 263022165554433 |
9 | 47504713606808 |
10 | 12303233112347 |
11 | 3a13854390281 |
12 | 1468547a6178b |
13 | 6b32612b1808 |
14 | 3076a02887d9 |
15 | 16507e36d9d2 |
hex | b3091d6d91b |
12303233112347 has 2 divisors, whose sum is σ = 12303233112348. Its totient is φ = 12303233112346.
The previous prime is 12303233112293. The next prime is 12303233112353. The reversal of 12303233112347 is 74321133230321.
12303233112347 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is an emirp because it is prime and its reverse (74321133230321) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 12303233112347 - 238 = 12028355205403 is a prime.
It is not a weakly prime, because it can be changed into another prime (12303233115347) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6151616556173 + 6151616556174.
It is an arithmetic number, because the mean of its divisors is an integer number (6151616556174).
Almost surely, 212303233112347 is an apocalyptic number.
12303233112347 is a deficient number, since it is larger than the sum of its proper divisors (1).
12303233112347 is an equidigital number, since it uses as much as digits as its factorization.
12303233112347 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54432, while the sum is 35.
Adding to 12303233112347 its reverse (74321133230321), we get a palindrome (86624366342668).
The spelling of 12303233112347 in words is "twelve trillion, three hundred three billion, two hundred thirty-three million, one hundred twelve thousand, three hundred forty-seven".
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