Base | Representation |
---|---|
bin | 1011001100001100111000… |
… | …0010100011110010101011 |
3 | 1121120021101212011121111202 |
4 | 2303003032002203302223 |
5 | 3103043042214110011 |
6 | 42100254035514415 |
7 | 2406644420551154 |
oct | 263031602436253 |
9 | 47507355147452 |
10 | 12304243113131 |
11 | 3a14222514872 |
12 | 146878a158a0b |
13 | 6b3392610a08 |
14 | 30775847a92b |
15 | 1650dcd7823b |
hex | b30ce0a3cab |
12304243113131 has 2 divisors, whose sum is σ = 12304243113132. Its totient is φ = 12304243113130.
The previous prime is 12304243113121. The next prime is 12304243113187. The reversal of 12304243113131 is 13131134240321.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12304243113131 - 210 = 12304243112107 is a prime.
It is a super-2 number, since 2×123042431131312 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 12304243113094 and 12304243113103.
It is not a weakly prime, because it can be changed into another prime (12304243113121) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6152121556565 + 6152121556566.
It is an arithmetic number, because the mean of its divisors is an integer number (6152121556566).
Almost surely, 212304243113131 is an apocalyptic number.
12304243113131 is a deficient number, since it is larger than the sum of its proper divisors (1).
12304243113131 is an equidigital number, since it uses as much as digits as its factorization.
12304243113131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5184, while the sum is 29.
Adding to 12304243113131 its reverse (13131134240321), we get a palindrome (25435377353452).
The spelling of 12304243113131 in words is "twelve trillion, three hundred four billion, two hundred forty-three million, one hundred thirteen thousand, one hundred thirty-one".
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