Base | Representation |
---|---|
bin | 11011111110100111011100… |
… | …101110101111110011111011 |
3 | 121010200111010111021221111222 |
4 | 123332213130232233303323 |
5 | 112112023323123230313 |
6 | 1113412254041142255 |
7 | 34630041123404312 |
oct | 3376473456576373 |
9 | 533614114257458 |
10 | 123050221305083 |
11 | 362313400177a6 |
12 | 11973b5a18a98b |
13 | 5387780803037 |
14 | 225593bc23279 |
15 | e35c42da6208 |
hex | 6fe9dcbafcfb |
123050221305083 has 2 divisors, whose sum is σ = 123050221305084. Its totient is φ = 123050221305082.
The previous prime is 123050221305059. The next prime is 123050221305097. The reversal of 123050221305083 is 380503122050321.
It is a strong prime.
It is an emirp because it is prime and its reverse (380503122050321) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 123050221305083 - 26 = 123050221305019 is a prime.
It is not a weakly prime, because it can be changed into another prime (123050221305283) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61525110652541 + 61525110652542.
It is an arithmetic number, because the mean of its divisors is an integer number (61525110652542).
Almost surely, 2123050221305083 is an apocalyptic number.
123050221305083 is a deficient number, since it is larger than the sum of its proper divisors (1).
123050221305083 is an equidigital number, since it uses as much as digits as its factorization.
123050221305083 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 43200, while the sum is 35.
The spelling of 123050221305083 in words is "one hundred twenty-three trillion, fifty billion, two hundred twenty-one million, three hundred five thousand, eighty-three".
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