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123051142345441 is a prime number
BaseRepresentation
bin11011111110101000010011…
…101000001111001011100001
3121010200120111200101122100211
4123332220103220033023201
5112112032214420023231
61113412525302214121
734630103006204212
oct3376502350171341
9533616450348324
10123051142345441
1136231772a0aa82
1211974176724341
13538789958552b
1422559c8299409
15e35c98b8beb1
hex6fea13a0f2e1

123051142345441 has 2 divisors, whose sum is σ = 123051142345442. Its totient is φ = 123051142345440.

The previous prime is 123051142345361. The next prime is 123051142345459. The reversal of 123051142345441 is 144543241150321.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 78613119891216 + 44438022454225 = 8866404^2 + 6666185^2 .

It is a cyclic number.

It is not a de Polignac number, because 123051142345441 - 215 = 123051142312673 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 123051142345394 and 123051142345403.

It is not a weakly prime, because it can be changed into another prime (123051142345141) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61525571172720 + 61525571172721.

It is an arithmetic number, because the mean of its divisors is an integer number (61525571172721).

Almost surely, 2123051142345441 is an apocalyptic number.

It is an amenable number.

123051142345441 is a deficient number, since it is larger than the sum of its proper divisors (1).

123051142345441 is an equidigital number, since it uses as much as digits as its factorization.

123051142345441 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 230400, while the sum is 40.

Adding to 123051142345441 its reverse (144543241150321), we get a palindrome (267594383495762).

The spelling of 123051142345441 in words is "one hundred twenty-three trillion, fifty-one billion, one hundred forty-two million, three hundred forty-five thousand, four hundred forty-one".