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12310010110393 is a prime number
BaseRepresentation
bin1011001100100010010111…
…0001111010000110111001
31121120211021202210102111221
42303020211301322012321
53103141400042013033
642103050210352041
72410240345326232
oct263104561720671
947524252712457
1012310010110393
113a16711871206
12146991958b621
136b3aa1338828
14307b44356089
151653292d812d
hexb3225c7a1b9

12310010110393 has 2 divisors, whose sum is σ = 12310010110394. Its totient is φ = 12310010110392.

The previous prime is 12310010110361. The next prime is 12310010110417. The reversal of 12310010110393 is 39301101001321.

12310010110393 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12299105112064 + 10904998329 = 3507008^2 + 104427^2 .

It is a cyclic number.

It is not a de Polignac number, because 12310010110393 - 25 = 12310010110361 is a prime.

It is a super-2 number, since 2×123100101103932 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (12310010110093) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6155005055196 + 6155005055197.

It is an arithmetic number, because the mean of its divisors is an integer number (6155005055197).

Almost surely, 212310010110393 is an apocalyptic number.

It is an amenable number.

12310010110393 is a deficient number, since it is larger than the sum of its proper divisors (1).

12310010110393 is an equidigital number, since it uses as much as digits as its factorization.

12310010110393 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 486, while the sum is 25.

The spelling of 12310010110393 in words is "twelve trillion, three hundred ten billion, ten million, one hundred ten thousand, three hundred ninety-three".