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123101121000314 = 261550560500157
BaseRepresentation
bin11011111111010110110110…
…100101101011001101111010
3121010212100111210001100222102
4123333112312211223031322
5112113342043434002224
61113451512502223402
734633522351566242
oct3377266645531572
9533770453040872
10123101121000314
113625098a624126
12119819a4424b62
13538c502a907b2
1422581a9c30b22
15e372217174ae
hex6ff5b696b37a

123101121000314 has 4 divisors (see below), whose sum is σ = 184651681500474. Its totient is φ = 61550560500156.

The previous prime is 123101121000293. The next prime is 123101121000331. The reversal of 123101121000314 is 413000121101321.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 103175476646089 + 19925644354225 = 10157533^2 + 4463815^2 .

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (31) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 30775280250077 + ... + 30775280250080.

Almost surely, 2123101121000314 is an apocalyptic number.

123101121000314 is a deficient number, since it is larger than the sum of its proper divisors (61550560500160).

123101121000314 is an equidigital number, since it uses as much as digits as its factorization.

123101121000314 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 61550560500159.

The product of its (nonzero) digits is 144, while the sum is 20.

Adding to 123101121000314 its reverse (413000121101321), we get a palindrome (536101242101635).

The spelling of 123101121000314 in words is "one hundred twenty-three trillion, one hundred one billion, one hundred twenty-one million, three hundred fourteen", and thus it is an aban number.

Divisors: 1 2 61550560500157 123101121000314