Base | Representation |
---|---|
bin | 10001111010011111110… |
… | …001001101110001000001 |
3 | 11100200112101001122222002 |
4 | 101322133301031301001 |
5 | 130132133012003231 |
6 | 2341311003353345 |
7 | 154640226626021 |
oct | 21723761156101 |
9 | 4320471048862 |
10 | 1231041125441 |
11 | 435099693076 |
12 | 17a701222855 |
13 | 8c118588b5a |
14 | 43822d47a81 |
15 | 2204ee1b0cb |
hex | 11e9fc4dc41 |
1231041125441 has 2 divisors, whose sum is σ = 1231041125442. Its totient is φ = 1231041125440.
The previous prime is 1231041125351. The next prime is 1231041125459. The reversal of 1231041125441 is 1445211401321.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1028814633025 + 202226492416 = 1014305^2 + 449696^2 .
It is an emirp because it is prime and its reverse (1445211401321) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1231041125441 - 214 = 1231041109057 is a prime.
It is not a weakly prime, because it can be changed into another prime (1231041124441) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 615520562720 + 615520562721.
It is an arithmetic number, because the mean of its divisors is an integer number (615520562721).
Almost surely, 21231041125441 is an apocalyptic number.
It is an amenable number.
1231041125441 is a deficient number, since it is larger than the sum of its proper divisors (1).
1231041125441 is an equidigital number, since it uses as much as digits as its factorization.
1231041125441 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3840, while the sum is 29.
Adding to 1231041125441 its reverse (1445211401321), we get a palindrome (2676252526762).
The spelling of 1231041125441 in words is "one trillion, two hundred thirty-one billion, forty-one million, one hundred twenty-five thousand, four hundred forty-one".
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