Base | Representation |
---|---|
bin | 10110111011100001… |
… | …00100010110001001 |
3 | 1011202221020200210002 |
4 | 23131300210112021 |
5 | 200202432243423 |
6 | 5353315132345 |
7 | 614030636501 |
oct | 133560442611 |
9 | 34687220702 |
10 | 12310431113 |
11 | 5247a10112 |
12 | 24768a40b5 |
13 | 1212575486 |
14 | 84ad48a01 |
15 | 4c0b40228 |
hex | 2ddc24589 |
12310431113 has 4 divisors (see below), whose sum is σ = 12958348560. Its totient is φ = 11662513668.
The previous prime is 12310431083. The next prime is 12310431143. The reversal of 12310431113 is 31113401321.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is an interprime number because it is at equal distance from previous prime (12310431083) and next prime (12310431143).
It is a cyclic number.
It is not a de Polignac number, because 12310431113 - 28 = 12310430857 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (12310431143) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 323958695 + ... + 323958732.
It is an arithmetic number, because the mean of its divisors is an integer number (3239587140).
Almost surely, 212310431113 is an apocalyptic number.
It is an amenable number.
12310431113 is a deficient number, since it is larger than the sum of its proper divisors (647917447).
12310431113 is an equidigital number, since it uses as much as digits as its factorization.
12310431113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 647917446.
The product of its (nonzero) digits is 216, while the sum is 20.
Adding to 12310431113 its reverse (31113401321), we get a palindrome (43423832434).
The spelling of 12310431113 in words is "twelve billion, three hundred ten million, four hundred thirty-one thousand, one hundred thirteen".
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