Base | Representation |
---|---|
bin | 1011001100100111001101… |
… | …0101010010100010101011 |
3 | 1121120221122110002012122111 |
4 | 2303021303111102202223 |
5 | 3103202031133344042 |
6 | 42103423250103151 |
7 | 2410314524555215 |
oct | 263116325224253 |
9 | 47527573065574 |
10 | 12311311231147 |
11 | 3a1721a264515 |
12 | 146a02127aab7 |
13 | 6b3c4aa76976 |
14 | 307c290895b5 |
15 | 1653a364a517 |
hex | b32735528ab |
12311311231147 has 2 divisors, whose sum is σ = 12311311231148. Its totient is φ = 12311311231146.
The previous prime is 12311311231139. The next prime is 12311311231201. The reversal of 12311311231147 is 74113211311321.
12311311231147 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12311311231147 - 23 = 12311311231139 is a prime.
It is not a weakly prime, because it can be changed into another prime (12311315231147) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6155655615573 + 6155655615574.
It is an arithmetic number, because the mean of its divisors is an integer number (6155655615574).
Almost surely, 212311311231147 is an apocalyptic number.
12311311231147 is a deficient number, since it is larger than the sum of its proper divisors (1).
12311311231147 is an equidigital number, since it uses as much as digits as its factorization.
12311311231147 is an evil number, because the sum of its binary digits is even.
The product of its digits is 3024, while the sum is 31.
Adding to 12311311231147 its reverse (74113211311321), we get a palindrome (86424522542468).
The spelling of 12311311231147 in words is "twelve trillion, three hundred eleven billion, three hundred eleven million, two hundred thirty-one thousand, one hundred forty-seven".
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