Base | Representation |
---|---|
bin | 10001111010100101001… |
… | …000111100101111101001 |
3 | 11100200202122121121122121 |
4 | 101322211020330233221 |
5 | 130132324043431012 |
6 | 2341323542551241 |
7 | 154642402551022 |
oct | 21724510745751 |
9 | 4320678547577 |
10 | 1231131233257 |
11 | 435135538442 |
12 | 17a727438521 |
13 | 8c131147ba3 |
14 | 43830cc1c49 |
15 | 22057cb9a07 |
hex | 11ea523cbe9 |
1231131233257 has 2 divisors, whose sum is σ = 1231131233258. Its totient is φ = 1231131233256.
The previous prime is 1231131233237. The next prime is 1231131233309. The reversal of 1231131233257 is 7523321311321.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1157649035481 + 73482197776 = 1075941^2 + 271076^2 .
It is a cyclic number.
It is not a de Polignac number, because 1231131233257 - 223 = 1231122844649 is a prime.
It is a super-2 number, since 2×12311312332572 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1231131233207) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 615565616628 + 615565616629.
It is an arithmetic number, because the mean of its divisors is an integer number (615565616629).
Almost surely, 21231131233257 is an apocalyptic number.
It is an amenable number.
1231131233257 is a deficient number, since it is larger than the sum of its proper divisors (1).
1231131233257 is an equidigital number, since it uses as much as digits as its factorization.
1231131233257 is an evil number, because the sum of its binary digits is even.
The product of its digits is 22680, while the sum is 34.
Adding to 1231131233257 its reverse (7523321311321), we get a palindrome (8754452544578).
The spelling of 1231131233257 in words is "one trillion, two hundred thirty-one billion, one hundred thirty-one million, two hundred thirty-three thousand, two hundred fifty-seven".
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