Base | Representation |
---|---|
bin | 1011001100101010001010… |
… | …0110110000111001101011 |
3 | 1121121000200201110100222011 |
4 | 2303022202212300321223 |
5 | 3103210142202403344 |
6 | 42104034101140351 |
7 | 2410343265104143 |
oct | 263124246607153 |
9 | 47530621410864 |
10 | 12312104341099 |
11 | 3a17596a19792 |
12 | 146a2029ba6b7 |
13 | 6b40461866b4 |
14 | 307ca253d923 |
15 | 1653ed0b0d34 |
hex | b32a29b0e6b |
12312104341099 has 2 divisors, whose sum is σ = 12312104341100. Its totient is φ = 12312104341098.
The previous prime is 12312104341073. The next prime is 12312104341169. The reversal of 12312104341099 is 99014340121321.
12312104341099 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12312104341099 - 233 = 12303514406507 is a prime.
It is a super-2 number, since 2×123121043410992 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (12312804341099) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6156052170549 + 6156052170550.
It is an arithmetic number, because the mean of its divisors is an integer number (6156052170550).
Almost surely, 212312104341099 is an apocalyptic number.
12312104341099 is a deficient number, since it is larger than the sum of its proper divisors (1).
12312104341099 is an equidigital number, since it uses as much as digits as its factorization.
12312104341099 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 46656, while the sum is 40.
The spelling of 12312104341099 in words is "twelve trillion, three hundred twelve billion, one hundred four million, three hundred forty-one thousand, ninety-nine".
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