Base | Representation |
---|---|
bin | 10110111011110100… |
… | …11001111101001001 |
3 | 1011210010002201100011 |
4 | 23131322121331021 |
5 | 200204112304433 |
6 | 5353450311521 |
7 | 614061600214 |
oct | 133572317511 |
9 | 34703081304 |
10 | 12313009993 |
11 | 5249411719 |
12 | 24777285a1 |
13 | 1212c6923b |
14 | 84b41a77b |
15 | 4c0e9e3cd |
hex | 2dde99f49 |
12313009993 has 2 divisors, whose sum is σ = 12313009994. Its totient is φ = 12313009992.
The previous prime is 12313009981. The next prime is 12313010069. The reversal of 12313009993 is 39990031321.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 8980026169 + 3332983824 = 94763^2 + 57732^2 .
It is a cyclic number.
It is not a de Polignac number, because 12313009993 - 221 = 12310912841 is a prime.
It is a super-2 number, since 2×123130099932 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (12313009903) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6156504996 + 6156504997.
It is an arithmetic number, because the mean of its divisors is an integer number (6156504997).
Almost surely, 212313009993 is an apocalyptic number.
It is an amenable number.
12313009993 is a deficient number, since it is larger than the sum of its proper divisors (1).
12313009993 is an equidigital number, since it uses as much as digits as its factorization.
12313009993 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 39366, while the sum is 40.
The spelling of 12313009993 in words is "twelve billion, three hundred thirteen million, nine thousand, nine hundred ninety-three".
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