12313011012113 has 4 divisors (see below), whose sum is σ = 14072012585280. Its totient is φ = 10554009438948.

The previous prime is 12313011012109. The next prime is 12313011012149. The reversal of 12313011012113 is 31121011031321.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 12313011012113 - 2² = 12313011012109 is a prime.

It is a super-3 number, since 3×12313011012113³ (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12313011012103) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 879500786573 + ... + 879500786586.

It is an arithmetic number, because the mean of its divisors is an integer number (3518003146320).

Almost surely, 2^{12313011012113} is an apocalyptic number.

It is an amenable number.

12313011012113 is a deficient number, since it is larger than the sum of its proper divisors (1759001573167).

12313011012113 is an equidigital number, since it uses as much as digits as its factorization.

12313011012113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1759001573166.

The product of its (nonzero) digits is 108, while the sum is 20.

Adding to 12313011012113 its reverse (31121011031321), we get a palindrome (43434022043434).

The spelling of 12313011012113 in words is "twelve trillion, three hundred thirteen billion, eleven million, twelve thousand, one hundred thirteen".