Base | Representation |
---|---|
bin | 10110111011110100… |
… | …11111010100111001 |
3 | 1011210010010211111222 |
4 | 23131322133110321 |
5 | 200204114010433 |
6 | 5353451001425 |
7 | 614062021313 |
oct | 133572372471 |
9 | 34703124458 |
10 | 12313031993 |
11 | 52494271a9 |
12 | 2477739275 |
13 | 1212c76262 |
14 | 84b4247b3 |
15 | 4c0ea5b98 |
hex | 2dde9f539 |
12313031993 has 2 divisors, whose sum is σ = 12313031994. Its totient is φ = 12313031992.
The previous prime is 12313031987. The next prime is 12313032007. The reversal of 12313031993 is 39913031321.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 11221588624 + 1091443369 = 105932^2 + 33037^2 .
It is a cyclic number.
It is not a de Polignac number, because 12313031993 - 24 = 12313031977 is a prime.
It is a super-2 number, since 2×123130319932 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (12313031923) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6156515996 + 6156515997.
It is an arithmetic number, because the mean of its divisors is an integer number (6156515997).
Almost surely, 212313031993 is an apocalyptic number.
It is an amenable number.
12313031993 is a deficient number, since it is larger than the sum of its proper divisors (1).
12313031993 is an equidigital number, since it uses as much as digits as its factorization.
12313031993 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 13122, while the sum is 35.
The spelling of 12313031993 in words is "twelve billion, three hundred thirteen million, thirty-one thousand, nine hundred ninety-three".
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