Base | Representation |
---|---|
bin | 10110111011110101… |
… | …11010100000010001 |
3 | 1011210010100111012221 |
4 | 23131322322200101 |
5 | 200204131041223 |
6 | 5353453221041 |
7 | 614062664002 |
oct | 133572724021 |
9 | 34703314187 |
10 | 12313143313 |
11 | 52494a28a9 |
12 | 2477791781 |
13 | 1212cb4b23 |
14 | 84b4531a9 |
15 | 4c0ec8b5d |
hex | 2ddeba811 |
12313143313 has 2 divisors, whose sum is σ = 12313143314. Its totient is φ = 12313143312.
The previous prime is 12313143281. The next prime is 12313143341. The reversal of 12313143313 is 31334131321.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 7958067264 + 4355076049 = 89208^2 + 65993^2 .
It is an emirp because it is prime and its reverse (31334131321) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 12313143313 - 25 = 12313143281 is a prime.
It is a super-2 number, since 2×123131433132 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (12313143113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6156571656 + 6156571657.
It is an arithmetic number, because the mean of its divisors is an integer number (6156571657).
Almost surely, 212313143313 is an apocalyptic number.
It is an amenable number.
12313143313 is a deficient number, since it is larger than the sum of its proper divisors (1).
12313143313 is an equidigital number, since it uses as much as digits as its factorization.
12313143313 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1944, while the sum is 25.
Adding to 12313143313 its reverse (31334131321), we get a palindrome (43647274634).
The spelling of 12313143313 in words is "twelve billion, three hundred thirteen million, one hundred forty-three thousand, three hundred thirteen".
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