Base | Representation |
---|---|
bin | 1011001100101110010010… |
… | …1100110011010100001011 |
3 | 1121121010120000000021000001 |
4 | 2303023210230303110023 |
5 | 3103214430041020412 |
6 | 42104340112223431 |
7 | 2410412621320432 |
oct | 263134454632413 |
9 | 47533500007001 |
10 | 12313213220107 |
11 | 3a18005948a18 |
12 | 146a47223ab77 |
13 | 6b4191b25917 |
14 | 307d69910119 |
15 | 1654655ec957 |
hex | b32e4b3350b |
12313213220107 has 2 divisors, whose sum is σ = 12313213220108. Its totient is φ = 12313213220106.
The previous prime is 12313213220057. The next prime is 12313213220137. The reversal of 12313213220107 is 70102231231321.
12313213220107 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is an emirp because it is prime and its reverse (70102231231321) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12313213220107 is a prime.
It is not a weakly prime, because it can be changed into another prime (12313213220137) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6156606610053 + 6156606610054.
It is an arithmetic number, because the mean of its divisors is an integer number (6156606610054).
Almost surely, 212313213220107 is an apocalyptic number.
12313213220107 is a deficient number, since it is larger than the sum of its proper divisors (1).
12313213220107 is an equidigital number, since it uses as much as digits as its factorization.
12313213220107 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3024, while the sum is 28.
Adding to 12313213220107 its reverse (70102231231321), we get a palindrome (82415444451428).
The spelling of 12313213220107 in words is "twelve trillion, three hundred thirteen billion, two hundred thirteen million, two hundred twenty thousand, one hundred seven".
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