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123132854718617 is a prime number
BaseRepresentation
bin11011111111110100011010…
…000100001101000010011001
3121010222101102100122021202112
4123333310122010031002121
5112114402041301443432
61113514241430042105
734636024633003352
oct3377643204150231
9533871370567675
10123132854718617
11362633944703a7
1211987b7baa9335
1353924bc3a96c3
14225993a61ad29
15e37e7c6557b2
hex6ffd1a10d099

123132854718617 has 2 divisors, whose sum is σ = 123132854718618. Its totient is φ = 123132854718616.

The previous prime is 123132854718529. The next prime is 123132854718647. The reversal of 123132854718617 is 716817458231321.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 65520671226256 + 57612183492361 = 8094484^2 + 7590269^2 .

It is a cyclic number.

It is not a de Polignac number, because 123132854718617 - 214 = 123132854702233 is a prime.

It is a super-3 number, since 3×1231328547186173 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (123132854718647) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61566427359308 + 61566427359309.

It is an arithmetic number, because the mean of its divisors is an integer number (61566427359309).

Almost surely, 2123132854718617 is an apocalyptic number.

It is an amenable number.

123132854718617 is a deficient number, since it is larger than the sum of its proper divisors (1).

123132854718617 is an equidigital number, since it uses as much as digits as its factorization.

123132854718617 is an evil number, because the sum of its binary digits is even.

The product of its digits is 13547520, while the sum is 59.

The spelling of 123132854718617 in words is "one hundred twenty-three trillion, one hundred thirty-two billion, eight hundred fifty-four million, seven hundred eighteen thousand, six hundred seventeen".