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12313403153 is a prime number
BaseRepresentation
bin10110111011110111…
…11001111100010001
31011210010211200122122
423131323321330101
5200204212400103
65353502544025
7614065125362
oct133573717421
934703750578
1012313403153
115249660047
122477898015
13121307618c
1484b4bdb69
154c102ab38
hex2ddef9f11

12313403153 has 2 divisors, whose sum is σ = 12313403154. Its totient is φ = 12313403152.

The previous prime is 12313403129. The next prime is 12313403173. The reversal of 12313403153 is 35130431321.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10166285584 + 2147117569 = 100828^2 + 46337^2 .

It is a cyclic number.

It is not a de Polignac number, because 12313403153 - 212 = 12313399057 is a prime.

It is a super-3 number, since 3×123134031533 (a number of 31 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (12313403173) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6156701576 + 6156701577.

It is an arithmetic number, because the mean of its divisors is an integer number (6156701577).

Almost surely, 212313403153 is an apocalyptic number.

It is an amenable number.

12313403153 is a deficient number, since it is larger than the sum of its proper divisors (1).

12313403153 is an equidigital number, since it uses as much as digits as its factorization.

12313403153 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3240, while the sum is 26.

Adding to 12313403153 its reverse (35130431321), we get a palindrome (47443834474).

The spelling of 12313403153 in words is "twelve billion, three hundred thirteen million, four hundred three thousand, one hundred fifty-three".