Base | Representation |
---|---|
bin | 10001111010110010001… |
… | …100110001111000011001 |
3 | 11100201022220220110011120 |
4 | 101322302030301320121 |
5 | 130133301141404040 |
6 | 2341401411115453 |
7 | 154651003130361 |
oct | 21726214617031 |
9 | 4321286813146 |
10 | 1231350341145 |
11 | 435238191441 |
12 | 17a7888a2b89 |
13 | 8c167662522 |
14 | 438520399a1 |
15 | 2206c14a7d0 |
hex | 11eb2331e19 |
1231350341145 has 16 divisors (see below), whose sum is σ = 1972189570752. Its totient is φ = 656043840320.
The previous prime is 1231350341131. The next prime is 1231350341149. The reversal of 1231350341145 is 5411430531321.
It is not a de Polignac number, because 1231350341145 - 232 = 1227055373849 is a prime.
It is a super-2 number, since 2×12313503411452 (a number of 25 digits) contains 22 as substring.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (1231350341149) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 42256302 + ... + 42285431.
It is an arithmetic number, because the mean of its divisors is an integer number (123261848172).
Almost surely, 21231350341145 is an apocalyptic number.
1231350341145 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
1231350341145 is a deficient number, since it is larger than the sum of its proper divisors (740839229607).
1231350341145 is an equidigital number, since it uses as much as digits as its factorization.
1231350341145 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 84542712.
The product of its (nonzero) digits is 21600, while the sum is 33.
Adding to 1231350341145 its reverse (5411430531321), we get a palindrome (6642780872466).
The spelling of 1231350341145 in words is "one trillion, two hundred thirty-one billion, three hundred fifty million, three hundred forty-one thousand, one hundred forty-five".
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