Base | Representation |
---|---|
bin | 10001111010110101001… |
… | …111110000000011111001 |
3 | 11100201110111002010202122 |
4 | 101322311033300003321 |
5 | 130133402232424034 |
6 | 2341410434411025 |
7 | 154652163432056 |
oct | 21726517600371 |
9 | 4321414063678 |
10 | 1231401451769 |
11 | 435264020625 |
12 | 17a7a1a30a75 |
13 | 8c1751192b8 |
14 | 43858b4202d |
15 | 2207189462e |
hex | 11eb53f00f9 |
1231401451769 has 2 divisors, whose sum is σ = 1231401451770. Its totient is φ = 1231401451768.
The previous prime is 1231401451723. The next prime is 1231401451801. The reversal of 1231401451769 is 9671541041321.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1227192037369 + 4209414400 = 1107787^2 + 64880^2 .
It is a cyclic number.
It is not a de Polignac number, because 1231401451769 - 212 = 1231401447673 is a prime.
It is a super-2 number, since 2×12314014517692 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1231401451069) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 615700725884 + 615700725885.
It is an arithmetic number, because the mean of its divisors is an integer number (615700725885).
Almost surely, 21231401451769 is an apocalyptic number.
It is an amenable number.
1231401451769 is a deficient number, since it is larger than the sum of its proper divisors (1).
1231401451769 is an equidigital number, since it uses as much as digits as its factorization.
1231401451769 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 181440, while the sum is 44.
The spelling of 1231401451769 in words is "one trillion, two hundred thirty-one billion, four hundred one million, four hundred fifty-one thousand, seven hundred sixty-nine".
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