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123141215425147 is a prime number
BaseRepresentation
bin11011111111111100001100…
…011001110001001001111011
3121011000012000000210011222221
4123333330030121301021323
5112120021202122101042
61113522143213024511
734636442053562143
oct3377741431611173
9534005000704887
10123141215425147
1136266994905a17
1211989713a85137
13539322258402a
14225a0d0b7b923
15e382bb651d67
hex6fff0c67127b

123141215425147 has 2 divisors, whose sum is σ = 123141215425148. Its totient is φ = 123141215425146.

The previous prime is 123141215425141. The next prime is 123141215425237. The reversal of 123141215425147 is 741524512141321.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 123141215425147 - 23 = 123141215425139 is a prime.

It is a super-2 number, since 2×1231412154251472 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (123141215425141) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61570607712573 + 61570607712574.

It is an arithmetic number, because the mean of its divisors is an integer number (61570607712574).

Almost surely, 2123141215425147 is an apocalyptic number.

123141215425147 is a deficient number, since it is larger than the sum of its proper divisors (1).

123141215425147 is an equidigital number, since it uses as much as digits as its factorization.

123141215425147 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 268800, while the sum is 43.

Adding to 123141215425147 its reverse (741524512141321), we get a palindrome (864665727566468).

The spelling of 123141215425147 in words is "one hundred twenty-three trillion, one hundred forty-one billion, two hundred fifteen million, four hundred twenty-five thousand, one hundred forty-seven".