Base | Representation |
---|---|
bin | 1011001101001000011100… |
… | …0011110101000110001011 |
3 | 1121121210200011022222101221 |
4 | 2303102013003311012023 |
5 | 3103323313411224003 |
6 | 42111500404022511 |
7 | 2411051560150354 |
oct | 263220703650613 |
9 | 47553604288357 |
10 | 12320232133003 |
11 | 3a1aa87940083 |
12 | 146b8b0991a37 |
13 | 6b4a40021212 |
14 | 308433b90d2b |
15 | 1657269007bd |
hex | b34870f518b |
12320232133003 has 2 divisors, whose sum is σ = 12320232133004. Its totient is φ = 12320232133002.
The previous prime is 12320232132947. The next prime is 12320232133103. The reversal of 12320232133003 is 30033123202321.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12320232133003 is a prime.
It is a super-2 number, since 2×123202321330032 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (12320232133103) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6160116066501 + 6160116066502.
It is an arithmetic number, because the mean of its divisors is an integer number (6160116066502).
Almost surely, 212320232133003 is an apocalyptic number.
12320232133003 is a deficient number, since it is larger than the sum of its proper divisors (1).
12320232133003 is an equidigital number, since it uses as much as digits as its factorization.
12320232133003 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3888, while the sum is 25.
Adding to 12320232133003 its reverse (30033123202321), we get a palindrome (42353355335324).
The spelling of 12320232133003 in words is "twelve trillion, three hundred twenty billion, two hundred thirty-two million, one hundred thirty-three thousand, three".
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