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1232052433 is a prime number
BaseRepresentation
bin100100101101111…
…1010000011010001
310011212022202012121
41021123322003101
510010401134213
6322131054241
742350162413
oct11133720321
93155282177
101232052433
11582509257
122a4741381
13168337711
14b98b49b3
157326c88d
hex496fa0d1

1232052433 has 2 divisors, whose sum is σ = 1232052434. Its totient is φ = 1232052432.

The previous prime is 1232052413. The next prime is 1232052467. The reversal of 1232052433 is 3342502321.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 909203409 + 322849024 = 30153^2 + 17968^2 .

It is an emirp because it is prime and its reverse (3342502321) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1232052433 - 221 = 1229955281 is a prime.

It is a super-2 number, since 2×12320524332 = 3035906395322438978, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1232052398 and 1232052407.

It is not a weakly prime, because it can be changed into another prime (1232052413) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 616026216 + 616026217.

It is an arithmetic number, because the mean of its divisors is an integer number (616026217).

Almost surely, 21232052433 is an apocalyptic number.

It is an amenable number.

1232052433 is a deficient number, since it is larger than the sum of its proper divisors (1).

1232052433 is an equidigital number, since it uses as much as digits as its factorization.

1232052433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4320, while the sum is 25.

The square root of 1232052433 is about 35100.6044534848. The cubic root of 1232052433 is about 1072.0368901247.

Adding to 1232052433 its reverse (3342502321), we get a palindrome (4574554754).

The spelling of 1232052433 in words is "one billion, two hundred thirty-two million, fifty-two thousand, four hundred thirty-three".