Base | Representation |
---|---|
bin | 1011001101001011101110… |
… | …0100000111100001100011 |
3 | 1121121212221112212021122221 |
4 | 2303102323210013201203 |
5 | 3103332114412343243 |
6 | 42112124032211511 |
7 | 2411112444411553 |
oct | 263227344074143 |
9 | 47555845767587 |
10 | 12321113012323 |
11 | 3a2039a0a2815 |
12 | 146bab7999b97 |
13 | 6b4b5068179b |
14 | 3084b8b71163 |
15 | 165778e01bed |
hex | b34bb907863 |
12321113012323 has 2 divisors, whose sum is σ = 12321113012324. Its totient is φ = 12321113012322.
The previous prime is 12321113012303. The next prime is 12321113012333. The reversal of 12321113012323 is 32321031112321.
12321113012323 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12321113012323 - 221 = 12321110915171 is a prime.
It is a super-2 number, since 2×123211130123232 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (12321113012303) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6160556506161 + 6160556506162.
It is an arithmetic number, because the mean of its divisors is an integer number (6160556506162).
Almost surely, 212321113012323 is an apocalyptic number.
12321113012323 is a deficient number, since it is larger than the sum of its proper divisors (1).
12321113012323 is an equidigital number, since it uses as much as digits as its factorization.
12321113012323 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1296, while the sum is 25.
Adding to 12321113012323 its reverse (32321031112321), we get a palindrome (44642144124644).
The spelling of 12321113012323 in words is "twelve trillion, three hundred twenty-one billion, one hundred thirteen million, twelve thousand, three hundred twenty-three".
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