Base | Representation |
---|---|
bin | 11100000001000001010111… |
… | …001000100010010100010001 |
3 | 121011021021200220112120020220 |
4 | 130001001113020202110101 |
5 | 112122230302303040103 |
6 | 1114020224534423253 |
7 | 34645011356165106 |
oct | 3401012710422421 |
9 | 534237626476226 |
10 | 123215483643153 |
11 | 36295436328390 |
12 | 1199bba0201b29 |
13 | 539a22a070a65 |
14 | 225d9385a6aad |
15 | e3a1b6819c53 |
hex | 701057222511 |
123215483643153 has 32 divisors (see below), whose sum is σ = 179977716252672. Its totient is φ = 74361710577600.
The previous prime is 123215483643149. The next prime is 123215483643169. The reversal of 123215483643153 is 351346384512321.
It is not a de Polignac number, because 123215483643153 - 22 = 123215483643149 is a prime.
It is a super-2 number, since 2×1232154836431532 (a number of 29 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 123215483643096 and 123215483643105.
It is not an unprimeable number, because it can be changed into a prime (123215483633153) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 11148738 + ... + 19254228.
It is an arithmetic number, because the mean of its divisors is an integer number (5624303632896).
Almost surely, 2123215483643153 is an apocalyptic number.
It is an amenable number.
123215483643153 is a deficient number, since it is larger than the sum of its proper divisors (56762232609519).
123215483643153 is a wasteful number, since it uses less digits than its factorization.
123215483643153 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8107445.
The product of its digits is 6220800, while the sum is 51.
The spelling of 123215483643153 in words is "one hundred twenty-three trillion, two hundred fifteen billion, four hundred eighty-three million, six hundred forty-three thousand, one hundred fifty-three".
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