Base | Representation |
---|---|
bin | 1011001101001111111010… |
… | …1111010001110010101001 |
3 | 1121121222212002111202210201 |
4 | 2303103332233101302221 |
5 | 3103341421420331213 |
6 | 42112431531512201 |
7 | 2411152410634342 |
oct | 263237657216251 |
9 | 47558762452721 |
10 | 12322240011433 |
11 | 3a20918278940 |
12 | 14701712b8661 |
13 | 6b4c9ccc6571 |
14 | 3085846db0c9 |
15 | 1657e2d1c6dd |
hex | b34febd1ca9 |
12322240011433 has 16 divisors (see below), whose sum is σ = 13452778800576. Its totient is φ = 11193426699840.
The previous prime is 12322240011413. The next prime is 12322240011443. The reversal of 12322240011433 is 33411004222321.
It is a de Polignac number, because none of the positive numbers 2k-12322240011433 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (12322240011413) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 86958666 + ... + 87100252.
It is an arithmetic number, because the mean of its divisors is an integer number (840798675036).
Almost surely, 212322240011433 is an apocalyptic number.
It is an amenable number.
12322240011433 is a deficient number, since it is larger than the sum of its proper divisors (1130538789143).
12322240011433 is a wasteful number, since it uses less digits than its factorization.
12322240011433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 147624.
The product of its (nonzero) digits is 6912, while the sum is 28.
Adding to 12322240011433 its reverse (33411004222321), we get a palindrome (45733244233754).
The spelling of 12322240011433 in words is "twelve trillion, three hundred twenty-two billion, two hundred forty million, eleven thousand, four hundred thirty-three".
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