Base | Representation |
---|---|
bin | 100100101110100… |
… | …1110010001111001 |
3 | 10011212222021110101 |
4 | 1021131032101321 |
5 | 10010443204213 |
6 | 322142315401 |
7 | 42353130301 |
oct | 11135162171 |
9 | 3155867411 |
10 | 1232397433 |
11 | 582724483 |
12 | 2a4888b61 |
13 | 168428767 |
14 | b9964601 |
15 | 732d9bdd |
hex | 4974e479 |
1232397433 has 2 divisors, whose sum is σ = 1232397434. Its totient is φ = 1232397432.
The previous prime is 1232397421. The next prime is 1232397469. The reversal of 1232397433 is 3347932321.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1062564409 + 169833024 = 32597^2 + 13032^2 .
It is an emirp because it is prime and its reverse (3347932321) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1232397433 - 25 = 1232397401 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1232397392 and 1232397401.
It is not a weakly prime, because it can be changed into another prime (1232397403) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 616198716 + 616198717.
It is an arithmetic number, because the mean of its divisors is an integer number (616198717).
Almost surely, 21232397433 is an apocalyptic number.
It is an amenable number.
1232397433 is a deficient number, since it is larger than the sum of its proper divisors (1).
1232397433 is an equidigital number, since it uses as much as digits as its factorization.
1232397433 is an evil number, because the sum of its binary digits is even.
The product of its digits is 81648, while the sum is 37.
The square root of 1232397433 is about 35105.5185547800. The cubic root of 1232397433 is about 1072.1369449061.
The spelling of 1232397433 in words is "one billion, two hundred thirty-two million, three hundred ninety-seven thousand, four hundred thirty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.080 sec. • engine limits •