Base | Representation |
---|---|
bin | 11100000001011001011010… |
… | …101100011110111101111011 |
3 | 121011100202101000102002221011 |
4 | 130001121122230132331323 |
5 | 112123141202134431133 |
6 | 1114040135551454351 |
7 | 34646614425623401 |
oct | 3401313254367573 |
9 | 534322330362834 |
10 | 123241313202043 |
11 | 362a5390454273 |
12 | 119a4baa5273b7 |
13 | 539c7b540940a |
14 | 2260ca8bb1471 |
15 | e3abc92526cd |
hex | 70165ab1ef7b |
123241313202043 has 2 divisors, whose sum is σ = 123241313202044. Its totient is φ = 123241313202042.
The previous prime is 123241313201953. The next prime is 123241313202053. The reversal of 123241313202043 is 340202313142321.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-123241313202043 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 123241313201996 and 123241313202014.
It is not a weakly prime, because it can be changed into another prime (123241313202053) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61620656601021 + 61620656601022.
It is an arithmetic number, because the mean of its divisors is an integer number (61620656601022).
Almost surely, 2123241313202043 is an apocalyptic number.
123241313202043 is a deficient number, since it is larger than the sum of its proper divisors (1).
123241313202043 is an equidigital number, since it uses as much as digits as its factorization.
123241313202043 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 20736, while the sum is 31.
Adding to 123241313202043 its reverse (340202313142321), we get a palindrome (463443626344364).
The spelling of 123241313202043 in words is "one hundred twenty-three trillion, two hundred forty-one billion, three hundred thirteen million, two hundred two thousand, forty-three".
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