Base | Representation |
---|---|
bin | 11100000001100110100100… |
… | …110010010011011000110011 |
3 | 121011102002211121121212222111 |
4 | 130001212210302103120303 |
5 | 112123404120413041342 |
6 | 1114050433514350151 |
7 | 34650624506266552 |
oct | 3401464462233063 |
9 | 534362747555874 |
10 | 123255441143347 |
11 | 36300380298717 |
12 | 119a7891a2b357 |
13 | 53a0c273929b6 |
14 | 226184926dd99 |
15 | e3b254709217 |
hex | 7019a4c93633 |
123255441143347 has 2 divisors, whose sum is σ = 123255441143348. Its totient is φ = 123255441143346.
The previous prime is 123255441143321. The next prime is 123255441143363. The reversal of 123255441143347 is 743341144552321.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 123255441143347 - 223 = 123255432754739 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 123255441143347.
It is not a weakly prime, because it can be changed into another prime (123255441141347) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61627720571673 + 61627720571674.
It is an arithmetic number, because the mean of its divisors is an integer number (61627720571674).
Almost surely, 2123255441143347 is an apocalyptic number.
123255441143347 is a deficient number, since it is larger than the sum of its proper divisors (1).
123255441143347 is an equidigital number, since it uses as much as digits as its factorization.
123255441143347 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 4838400, while the sum is 49.
Adding to 123255441143347 its reverse (743341144552321), we get a palindrome (866596585695668).
The spelling of 123255441143347 in words is "one hundred twenty-three trillion, two hundred fifty-five billion, four hundred forty-one million, one hundred forty-three thousand, three hundred forty-seven".
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