Base | Representation |
---|---|
bin | 1011001101011111010000… |
… | …0100100011100000110011 |
3 | 1121122101110221111000012121 |
4 | 2303113310010203200303 |
5 | 3103423334114210323 |
6 | 42114352203535111 |
7 | 2411356410213325 |
oct | 263276404434063 |
9 | 47571427430177 |
10 | 12326356006963 |
11 | 3a2263a689239 |
12 | 1470b1b82a497 |
13 | 6b54a796c28b |
14 | 308855207615 |
15 | 165984356a5d |
hex | b35f4123833 |
12326356006963 has 2 divisors, whose sum is σ = 12326356006964. Its totient is φ = 12326356006962.
The previous prime is 12326356006957. The next prime is 12326356007047. The reversal of 12326356006963 is 36960065362321.
It is a weak prime.
It is an emirp because it is prime and its reverse (36960065362321) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 12326356006963 - 29 = 12326356006451 is a prime.
It is a super-3 number, since 3×123263560069633 (a number of 40 digits) contains 333 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 12326356006963.
It is not a weakly prime, because it can be changed into another prime (12326356006163) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6163178003481 + 6163178003482.
It is an arithmetic number, because the mean of its divisors is an integer number (6163178003482).
Almost surely, 212326356006963 is an apocalyptic number.
12326356006963 is a deficient number, since it is larger than the sum of its proper divisors (1).
12326356006963 is an equidigital number, since it uses as much as digits as its factorization.
12326356006963 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6298560, while the sum is 52.
The spelling of 12326356006963 in words is "twelve trillion, three hundred twenty-six billion, three hundred fifty-six million, six thousand, nine hundred sixty-three".
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