Search a number
-
+
123310002020113 is a prime number
BaseRepresentation
bin11100000010011001011000…
…110111100001111100010001
3121011121022200001112121100001
4130002121120313201330101
5112130302341004120423
61114131455523330001
734654565542141246
oct3402313067417421
9534538601477301
10123310002020113
1136321529500a07
12119b637a220901
1353a611100226c
1422643435d55cd
15e3c8996b4cad
hex702658de1f11

123310002020113 has 2 divisors, whose sum is σ = 123310002020114. Its totient is φ = 123310002020112.

The previous prime is 123310002020089. The next prime is 123310002020167. The reversal of 123310002020113 is 311020200013321.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 101447943746769 + 21862058273344 = 10072137^2 + 4675688^2 .

It is an emirp because it is prime and its reverse (311020200013321) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 123310002020113 - 29 = 123310002019601 is a prime.

It is not a weakly prime, because it can be changed into another prime (123310002023113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61655001010056 + 61655001010057.

It is an arithmetic number, because the mean of its divisors is an integer number (61655001010057).

Almost surely, 2123310002020113 is an apocalyptic number.

It is an amenable number.

123310002020113 is a deficient number, since it is larger than the sum of its proper divisors (1).

123310002020113 is an equidigital number, since it uses as much as digits as its factorization.

123310002020113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 123310002020113 its reverse (311020200013321), we get a palindrome (434330202033434).

The spelling of 123310002020113 in words is "one hundred twenty-three trillion, three hundred ten billion, two million, twenty thousand, one hundred thirteen".