Base | Representation |
---|---|
bin | 11100000010011010011100… |
… | …001110100100001010100011 |
3 | 121011121102120211001020101222 |
4 | 130002122130032210022203 |
5 | 112130312144311211003 |
6 | 1114132204013445255 |
7 | 34654635544010144 |
oct | 3402323416441243 |
9 | 534542524036358 |
10 | 123311132132003 |
11 | 36321a59412782 |
12 | 119b66347a082b |
13 | 53a6261196b1a |
14 | 226440d731acb |
15 | e3c9139e7c38 |
hex | 70269c3a42a3 |
123311132132003 has 4 divisors (see below), whose sum is σ = 123311156127768. Its totient is φ = 123311108136240.
The previous prime is 123311132131987. The next prime is 123311132132017. The reversal of 123311132132003 is 300231231113321.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 123311132132003 - 24 = 123311132131987 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (123311132132033) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 815426 + ... + 15725367.
It is an arithmetic number, because the mean of its divisors is an integer number (30827789031942).
Almost surely, 2123311132132003 is an apocalyptic number.
123311132132003 is a deficient number, since it is larger than the sum of its proper divisors (23995765).
123311132132003 is an equidigital number, since it uses as much as digits as its factorization.
123311132132003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 23995764.
The product of its (nonzero) digits is 1944, while the sum is 26.
Adding to 123311132132003 its reverse (300231231113321), we get a palindrome (423542363245324).
The spelling of 123311132132003 in words is "one hundred twenty-three trillion, three hundred eleven billion, one hundred thirty-two million, one hundred thirty-two thousand, three".
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