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1233113551393 is a prime number
BaseRepresentation
bin10001111100011011010…
…010111001001000100001
311100212212210200210220211
4101330123102321020201
5130200404032121033
62342252354534121
7155042463150133
oct21743322711041
94325783623824
101233113551393
11435a624a8399
1217ab9b297341
138c388a40cb9
144397c297053
1522121d382cd
hex11f1b4b9221

1233113551393 has 2 divisors, whose sum is σ = 1233113551394. Its totient is φ = 1233113551392.

The previous prime is 1233113551367. The next prime is 1233113551489. The reversal of 1233113551393 is 3931553113321.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 747927469584 + 485186081809 = 864828^2 + 696553^2 .

It is an emirp because it is prime and its reverse (3931553113321) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1233113551393 - 213 = 1233113543201 is a prime.

It is not a weakly prime, because it can be changed into another prime (1233113551343) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 616556775696 + 616556775697.

It is an arithmetic number, because the mean of its divisors is an integer number (616556775697).

Almost surely, 21233113551393 is an apocalyptic number.

It is an amenable number.

1233113551393 is a deficient number, since it is larger than the sum of its proper divisors (1).

1233113551393 is an equidigital number, since it uses as much as digits as its factorization.

1233113551393 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 109350, while the sum is 40.

The spelling of 1233113551393 in words is "one trillion, two hundred thirty-three billion, one hundred thirteen million, five hundred fifty-one thousand, three hundred ninety-three".