Base | Representation |
---|---|
bin | 1011001101110001010110… |
… | …0010111111101011101001 |
3 | 1121122212000102000121021011 |
4 | 2303130111202333223221 |
5 | 3104013310411231324 |
6 | 42120514133343521 |
7 | 2411620641456643 |
oct | 263342542775351 |
9 | 47585012017234 |
10 | 12331212602089 |
11 | 3a24702049017 |
12 | 1471a56197ba1 |
13 | 6b5a9cb9aac4 |
14 | 308b96219893 |
15 | 165b6a8d2c94 |
hex | b37158bfae9 |
12331212602089 has 2 divisors, whose sum is σ = 12331212602090. Its totient is φ = 12331212602088.
The previous prime is 12331212602047. The next prime is 12331212602099. The reversal of 12331212602089 is 98020621213321.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 12313137144064 + 18075458025 = 3509008^2 + 134445^2 .
It is a cyclic number.
It is not a de Polignac number, because 12331212602089 - 211 = 12331212600041 is a prime.
It is not a weakly prime, because it can be changed into another prime (12331212602099) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6165606301044 + 6165606301045.
It is an arithmetic number, because the mean of its divisors is an integer number (6165606301045).
Almost surely, 212331212602089 is an apocalyptic number.
It is an amenable number.
12331212602089 is a deficient number, since it is larger than the sum of its proper divisors (1).
12331212602089 is an equidigital number, since it uses as much as digits as its factorization.
12331212602089 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 62208, while the sum is 40.
The spelling of 12331212602089 in words is "twelve trillion, three hundred thirty-one billion, two hundred twelve million, six hundred two thousand, eighty-nine".
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